What is the sum of the geometric sequence 1, 3, 9 if there are 12 terms?

The sum of a geometric sequence can be calculated using the formula:

S = a * (1 – r^n) / (1 – r)

where:

  • S is the sum of the sequence.
  • a is the first term of the sequence.
  • r is the common ratio.
  • n is the number of terms.

In this case, the terms of the sequence are:

  • First term (a) = 1
  • Second term = 3
  • Third term = 9

From these terms, we can see that the common ratio (r) can be calculated as follows:

  • r = Second term / First term = 3 / 1 = 3
  • r = Third term / Second term = 9 / 3 = 3

Now, we know:

  • a = 1
  • r = 3
  • n = 12

Substituting these values into the formula gives:

S = 1 * (1 – 3^12) / (1 – 3)

Now we calculate:

  • 3^12 = 531441
  • 1 – 531441 = -531440
  • S = 1 * (-531440) / -2
  • S = 531440 / 2 = 265720

So, the sum of the geometric sequence with 12 terms is 265720.

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