Which function in vertex form is equivalent to f(x) = x² + 16x + 8?

To express the function in vertex form, we can start by rewriting the quadratic function. The given function is:

f(x) = x² + 16x + 8

First, we need to complete the square. We take the coefficient of the x term, which is 16, divide it by 2 (getting 8), and then square it (resulting in 64).

We can rewrite the function as:

f(x) = (x² + 16x + 64) – 64 + 8

This simplifies to:

f(x) = (x + 8)² – 56

Now, we have the function in vertex form, which is:

f(x) = (x + 8)² – 56

In vertex form, the function clearly shows the vertex of the parabola at the point (-8, -56).

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