What would Jow’s weight be if he doubled his distance from the center of the Earth?

Jow has a weight of 720 N (around 162 lbs) when standing on the surface of the Earth. To understand how his weight changes if he doubles his distance from the center of the Earth, we need to consider how gravitational force works.

The force of gravity decreases with the square of the distance from the center of the Earth. This means that if you double the distance, the gravitational force becomes one-fourth of what it was originally.

So, if Jow is currently experiencing a gravitational force of 720 N, when he doubles his distance from the Earth’s center, his weight would be calculated as follows:

New Weight = Original Weight / (Distance Factor)^2

In this case, the distance factor is 2, so:

New Weight = 720 N / (2)^2 = 720 N / 4 = 180 N

Therefore, if Jow doubles his distance from the Earth’s center, his weight would be 180 N. This demonstrates how dramatically weight can change with distance from the gravitational source.

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