What value is missing from Samuel’s solution when finding the difference of the polynomials 15x² + 11y² + 8x – 7x² – 5y² – 2x – x² – 6y² – 6x?

To find the difference of the polynomials, we first need to combine like terms. Let’s organize the polynomials Samuel is working with:

  • 15x²
  • 11y²
  • 8x
  • -7x²
  • -5y²
  • -2x
  • -x²
  • -6y²
  • -6x

Now we can group them:

  • For x² terms: 15x² – 7x² – x² = 15x² – 8x² = 7x²
  • For y² terms: 11y² – 5y² – 6y² = 11y² – 11y² = 0
  • For x terms: 8x – 2x – 6x = 8x – 8x = 0

After combining these, we get:

  • 7x²
  • 0 for y²
  • 0 for x

Therefore, the final expression is simply:

7x²

In Samuel’s solution, the key value missing was the recognition that the y² and x terms cancel out to zero, leaving only the x² term. Thus, the complete final polynomial represents just the x² component: 7x².

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