What percentage chance is there for the offspring if the father is heterozygous and a mother is a homozygous recessive to inherit a trait?

To determine the percentage chance of the offspring inheriting a trait when the father is heterozygous (Tt) and the mother is homozygous recessive (tt), we can use a simple Punnett square.

First, let’s denote the alleles:

• Let ‘T’ represent the dominant allele.
• Let ‘t’ represent the recessive allele.

The father’s genotype is heterozygous (Tt), meaning he has one dominant allele (T) and one recessive allele (t). The mother’s genotype is homozygous recessive (tt), meaning she has two recessive alleles.

Next, we can set up a Punnett square:

From the Punnett square, we see that:

• 50% of the offspring (2 out of 4) will inherit the genotype Tt (heterozygous)
• 50% of the offspring (2 out of 4) will inherit the genotype tt (homozygous recessive)

Therefore, there is a 50% chance that the offspring will inherit the dominant trait (Tt) and a 50% chance that they will inherit the recessive trait (tt).