What is the value of y in the equation 6 + 4x – 2 + 8y = 44 when x = 3?

To find the value of y when x = 3, we first need to substitute x into the equation.

The equation is:

6 + 4x – 2 + 8y = 44

Substituting x with 3 gives us:

6 + 4(3) – 2 + 8y = 44

Now, we simplify the equation:

6 + 12 – 2 + 8y = 44

This simplifies to:

16 + 8y = 44

Next, we subtract 16 from both sides:

8y = 44 – 16

8y = 28

Now, we divide both sides by 8:

y = 28 / 8

y = 3.5

So, the value of y in the equation when x = 3 is 3.5.

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