What is the prime factorization of 325?

The prime factorization of 325 is 5 × 5 × 13 or 52 × 13.

To arrive at this conclusion, we start by dividing 325 by the smallest prime number, which is 5. Since 325 ends in a 5, it’s divisible by 5. Performing the division:

325 ÷ 5 = 65

Next, we factor 65 further by dividing it by 5 again:

65 ÷ 5 = 13

At this point, we are left with the number 13, which is itself a prime number. Therefore, we cannot factor it any further. Thus, the prime factors of 325 are 5 (which we found twice) and 13.

In summary, the prime factorization of 325 is expressed as 52 × 13.

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