What is the axis of symmetry for the function f(x) = 2x² + 8x + 8?

The axis of symmetry for the quadratic function f(x) = 2x² + 8x + 8 can be found using the formula:

x = -b / (2a)

In the equation f(x) = 2x² + 8x + 8, the coefficients are:

  • a = 2
  • b = 8

Now, substituting the values of a and b into the formula gives:

x = -8 / (2 * 2)

This simplifies to:

x = -8 / 4 = -2

Therefore, the axis of symmetry for the function is x = -2. This means that the graph of the function is symmetric around the vertical line x = -2. In other words, if you were to fold the graph along this line, the two halves would match up perfectly.

More Related Questions