What are the dimensions of a poster if the top and bottom margins are each 9 cm and the side margins are each 6 cm, given that the area of printed material is fixed at 864 cm²?

To find the dimensions of the poster, we start with the information provided:

  • Top and bottom margins: 9 cm each
  • Side margins: 6 cm each
  • Area of printed material: 864 cm²

Let the width of the poster be w cm and the height be h cm.

The printed area is determined by subtracting the margins from the total dimensions of the poster. The width of the printed area is:

Width of printed area = w – 2 * (side margins) = w – 2 * 6 = w – 12 cm

The height of the printed area is:

Height of printed area = h – 2 * (top and bottom margins) = h – 2 * 9 = h – 18 cm

Now, the area of the printed material can be expressed as:

(w – 12)(h – 18) = 864

Expanding this, we get:

wh – 18w – 12h + 216 = 864

Which simplifies to:

wh – 18w – 12h = 648

Next, we express h in terms of w:

h = (648 + 18w + 12h) / w

To find realistic dimensions, let’s assume a reasonable width. For instance, let’s try w = 48 cm:

Substituting w = 48 into the area equation:

(48 – 12)(h – 18) = 864

36(h – 18) = 864

h – 18 = 24

h = 42 cm

Therefore, when we check our dimensions:

  • Width of the poster: 48 cm
  • Height of the poster: 42 cm

Finally, the dimensions of the poster are:

  • Width: 48 cm
  • Height: 42 cm

This ensures that the area of printed material remains fixed at 864 cm² with the given margins.

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