Yes, Ba(OH)2 (barium hydroxide) is considered a strong electrolyte. This means that when it dissolves in water, it completely dissociates into its constituent ions.
In a 0.850 M solution of Ba(OH)2, the dissociation can be represented by the following equation:
Ba(OH)2 (s) → Ba2+ (aq) + 2 OH– (aq)
From this equation, we can see that one molecule of barium hydroxide produces one barium ion (Ba2+) and two hydroxide ions (OH–).
Therefore, in a 0.850 M solution of Ba(OH)2:
- The concentration of Ba2+ is 0.850 M.
- The concentration of OH– ions is 2 × 0.850 M = 1.700 M.
In conclusion, the concentrations of the individual ions in a 0.850 M Ba(OH)2 solution are:
- Ba2+: 0.850 M
- OH–: 1.700 M