To calculate the capacitance of a parallel plate capacitor, we can use the formula:
C = ε0 * (A / d)
Where:
- C = capacitance in farads (F)
- ε0 = permittivity of free space (approximately 8.854 x 10-12 F/m)
- A = area of one of the plates in square meters (m2)
- d = distance between the plates in meters (m)
Given:
- Plate dimensions: 20 cm x 30 cm = 0.2 m x 0.3 m
- Distance between plates: 10 mm = 0.01 m
- Voltage (V) = 12 V
Now, let’s calculate the area (A):
A = 0.2 m * 0.3 m = 0.06 m2
Now, substitute into the capacitance formula:
C = 8.854 x 10-12 F/m * (0.06 m2 / 0.01 m)
C = 8.854 x 10-12 F/m * 6 = 5.3124 x 10-11 F
So, the capacitance is approximately 53.124 pF (picoFarads).
Next, to find the charge (Q) on each plate, we use the formula:
Q = C * V
Substituting our known values:
Q = 5.3124 x 10-11 F * 12 V
Q = 6.37488 x 10-10 C
Rounded to three significant figures, the charge on each plate is approximately 637 pC (picoCoulombs).