How do you solve the system of equations 2x + y = 3 and x + 2y = 1?

To solve the system of equations:

  • 2x + y = 3 (1)
  • x + 2y = 1 (2)

We can use the method of substitution or elimination. Here, we’ll use the elimination method.

First, we can rearrange equation (1) for y:

y = 3 – 2x

Next, we substitute this expression for y into equation (2):

x + 2(3 – 2x) = 1

x + 6 – 4x = 1

-3x + 6 = 1

-3x = 1 – 6

-3x = -5

x = 5/3

Now that we have the value of x, we can substitute it back into the rearranged equation for y:

y = 3 – 2(5/3)

y = 3 – 10/3

y = 9/3 – 10/3

y = -1/3

Thus, the solution to the system of equations is:

x = 5/3 and y = -1/3

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