Find the point (x, y) on the unit circle that corresponds to the real number t = 2π/3

The unit circle is defined as the set of all points in the Cartesian plane that are at a distance of 1 from the origin (0, 0). The equation for the unit circle is given by:

x² + y² = 1

To find the point (x, y) corresponding to the angle t = 2π/3, we can use the parametric equations of the unit circle:

x = cos(t)

y = sin(t)

Now, substituting t = 2π/3 into these equations, we can calculate the coordinates:

  • x = cos(2π/3).

Since 2π/3 is in the second quadrant, where cosine is negative, we find:

  • cos(2π/3) = -1/2

y = sin(2π/3).

In the second quadrant, sine is positive, so:

  • sin(2π/3) = √3/2

Thus, the coordinates (x, y) on the unit circle that correspond to t = 2π/3 are:

  • x = -1/2
  • y = √3/2

In conclusion, the point on the unit circle corresponding to the angle t = 2π/3 is (-1/2, √3/2).

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