To find the equation of a line given a point and a slope, we can use the point-slope form of the linear equation, which is:
y – y1 = m(x – x1)
In this formula, (x1, y1) is the point through which the line passes, and m is the slope of the line.
For our problem, we have:
- Point: (4, 3) => x1 = 4, y1 = 3
- Slope: m = 12
Substituting these values into the point-slope formula, we get:
y – 3 = 12(x – 4)
Now, let’s simplify the equation:
y – 3 = 12x – 48
To isolate y, we add 3 to both sides:
y = 12x – 48 + 3
y = 12x – 45
So, the equation of the line that passes through the point (4, 3) with a slope of 12 is:
y = 12x – 45