The Lewis dot diagram for the N3− anion can be drawn by following several steps:
- Count the total number of valence electrons in the nitrogen atom. Nitrogen (N) is in group 15 of the periodic table and has five valence electrons.
- Since there are three nitrogen atoms in the N3− anion, we multiply the number of valence electrons by three: 5 electrons/atom × 3 atoms = 15 valence electrons.
- Next, account for the extra three electrons due to the negative charge of the anion: 15 electrons + 3 electrons = 18 valence electrons total.
- To create the diagram, we’ll arrange the three nitrogen atoms in a row and start bonding them together. Each bond represents two electrons. So, we’ll form a triple bond between the two outer nitrogen atoms.
- Distribute the remaining electrons: each nitrogen in the triple bond has a complete octet. Now, place the extra electron pairs around the central nitrogen atom.
The final Lewis structure shows the three nitrogen atoms bonded in a linear fashion with one nitrogen atom in the center and the other two bonded by triple bonds, giving each nitrogen atom an octet:
N≡N−N
The nitrogen atoms in the N3− anion share those electrons, achieving stability through a complete octet. This shared electron configuration demonstrates how the N3− anion achieves a negative charge and stability in its structure.