Identify the Surface with the Given Vector Equation r(s,t) = (s sin(9t), s^2, s cos(9t))

The given vector equation can be analyzed to identify the surface it represents. The equation is:

r(s,t) = (s sin(9t), s^2, s cos(9t))

To understand the surface, we start by examining the components of the vector:

  • The first component is x = s sin(9t).
  • The second component is y = s^2.
  • The third component is z = s cos(9t).

From the second component, we see that y = s^2, which suggests a parabolic relationship because it squares the variable s. This indicates that the surface opens up in the y-direction as s varies.

Next, if we eliminate s from the first and third components, we can express x and z in terms of y:

  • From y = s^2, we can express s = √y.
  • Substituting this into the equations for x and z:
    x = √y sin(9t) and z = √y cos(9t).

Now we can rewrite this system by using the identities of sine and cosine:

Using the fact that sin²(θ) + cos²(θ) = 1, we can form:

sin²(9t) + cos²(9t) = 1.

Thus, if we consider x and z:

x² + z² = y

This equation describes a circular cylinder along the y-axis. The angle 9t indicates that the circle formed by the projections of points in the xz-plane completes a full revolution as t varies, creating a helical structure along the y-axis.

In conclusion, the surface represented by the vector equation is a parabolic cylinder that is also helical in the xz-plane, indicated by the trigonometric functions of 9t.

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