Find the First Partial Derivatives of the Function z = x sin(xy)

To find the first partial derivatives of the function z = x sin(xy), we need to take the derivatives with respect to each variable: x, y, and z.

Partial Derivative with respect to x (∂z/∂x)

We apply the product rule and the chain rule here:

  • Let u = x and v = sin(xy).

Then, we have:

  • ∂z/∂x = u’v + uv’

Where:

  • u’ = 1 (derivative of x)
  • v’ = cos(xy) * (y) (from chain rule)

Thus, substituting in:

  • ∂z/∂x = 1 * sin(xy) + x * cos(xy) * y

So, the first partial derivative with respect to x is:

  • ∂z/∂x = sin(xy) + xy cos(xy)

Partial Derivative with respect to y (∂z/∂y)

In this case, we regard x as a constant and differentiate with respect to y:

  • z = x sin(xy)

Using the chain rule, we get:

  • ∂z/∂y = x * cos(xy) * (x)

So, the first partial derivative with respect to y is:

  • ∂z/∂y = x^2 cos(xy)

Final Result

The first partial derivatives of the function z = x sin(xy) are:

  • ∂z/∂x = sin(xy) + xy cos(xy)
  • ∂z/∂y = x^2 cos(xy)

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