Find the equation of the line that passes through the given point (4, 3) with slope 12

To find the equation of a line given a point and a slope, we can use the point-slope form of the linear equation, which is:

y – y1 = m(x – x1)

In this formula, (x1, y1) is the point through which the line passes, and m is the slope of the line.

For our problem, we have:

  • Point: (4, 3) => x1 = 4, y1 = 3
  • Slope: m = 12

Substituting these values into the point-slope formula, we get:

y – 3 = 12(x – 4)

Now, let’s simplify the equation:

y – 3 = 12x – 48

To isolate y, we add 3 to both sides:

y = 12x – 48 + 3

y = 12x – 45

So, the equation of the line that passes through the point (4, 3) with a slope of 12 is:

y = 12x – 45

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