Identify all the roots of gx = x² + 3x + 4x² + 4x + 29

To find the roots of the function gx = x² + 3x + 4x² + 4x + 29, we first need to simplify the expression.

Combine like terms:

  • 4x² + x² = 5x²
  • 3x + 4x = 7x

This gives us the simplified function:

gx = 5x² + 7x + 29

Next, we need to determine the roots of this quadratic equation.

We can use the quadratic formula:

x = (-b ± √(b² – 4ac)) / 2a

Here, a = 5, b = 7, and c = 29.

Now, we calculate the discriminant, b² – 4ac:

Discriminant = 7² – 4 * 5 * 29

Calculating this gives:

Discriminant = 49 – 580 = -531

Since the discriminant is negative, it indicates that the quadratic equation has no real roots. Instead, it has two complex roots.

We can further calculate the complex roots.

  • The real part will be -b/(2a) = -7/(2*5) = -7/10
  • The imaginary part will be √(-531)/(2*5) = √(531)i/10

Thus, the roots of the function gx are:

  • x = -7/10 + √531i/10
  • x = -7/10 – √531i/10

In conclusion, the roots of the equation gx = x² + 3x + 4x² + 4x + 29 are complex numbers due to the negative discriminant.

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