How far apart are the foci of an ellipse with a major axis of 10 feet and a minor axis of 6 feet?

To find the distance between the foci of an ellipse, we can use the formula:

c = √(a² – b²)

where:

  • c is the distance from the center to each focus,
  • a is half the length of the major axis, and
  • b is half the length of the minor axis.

In this case, the major axis is 10 feet, so:

a = 10/2 = 5 feet

The minor axis is 6 feet, so:

b = 6/2 = 3 feet

Now we can plug these values into the formula:

c = √(5² – 3²)

c = √(25 – 9)

c = √16

c = 4 feet

The total distance between the two foci is twice the distance from the center to a focus:

Distance between foci = 2c = 2 * 4 = 8 feet

Therefore, the foci of this ellipse are 8 feet apart.

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