What are the foci of the ellipse graph x²/49 + y²/64 = 1?

To determine the foci of the ellipse given by the equation x²/49 + y²/64 = 1, we first need to identify the values of a² and b² from the standard form of the ellipse equation.

This equation can be rewritten in the standard form as:

x²/a² + y²/b² = 1

From x²/49, we see that a² = 49. Thus, a = √49 = 7.

From y²/64, we see that b² = 64. Thus, b = √64 = 8.

For an ellipse, the distance to the foci is given by the formula:

c = √(b² – a²)

Substituting our values:

c = √(64 – 49) = √15

The foci of the ellipse are located along the major axis, which in this case is along the y-axis since b > a. The coordinates of the foci, therefore, are:

(0, ±c) = (0, ±√15)

Thus, the foci of the ellipse x²/49 + y²/64 = 1 are at the points (0, √15) and (0, -√15).

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