What is the length of one side of a rhombus if diagonals ef and fh are 16 and 12, respectively?

To find the length of one side of the rhombus, we can use the properties of a rhombus and the Pythagorean theorem. In a rhombus, the diagonals bisect each other at right angles.

Given the lengths of the diagonals ef = 16 and fh = 12, we first find their half-lengths. The half-lengths of the diagonals are:

  • Half of ef = 16 / 2 = 8
  • Half of fh = 12 / 2 = 6

Now, we can form a right triangle using these half-lengths as the two legs of the triangle. The length of one side of the rhombus will be the hypotenuse of this right triangle.

Using the Pythagorean theorem:

c² = a² + b²

Where:

  • c = length of one side of the rhombus
  • a = half of ef = 8
  • b = half of fh = 6

Substituting the values:

c² = 8² + 6²

c² = 64 + 36

c² = 100

c = √100

c = 10

Therefore, the length of one side of the rhombus is 10 units.

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