How do you find and simplify the difference quotient f(x + h) – f(x) where h is not equal to zero for the function f(x) = x² + 5?

To find and simplify the difference quotient for the function f(x) = x² + 5, we will first calculate f(x + h) and then use it to find the difference quotient f(x + h) – f(x) / h.

1. **Calculate f(x + h):**
We start with the function:

f(x) = x² + 5

Now, substituting x + h into the function:

f(x + h) = (x + h)² + 5

This can be expanded:

f(x + h) = x² + 2xh + h² + 5

2. **Find f(x + h) – f(x):**
Next, we compute:

f(x + h) – f(x) = (x² + 2xh + h² + 5) – (x² + 5)

By simplifying this expression, we get:

f(x + h) – f(x) = 2xh + h²

3. **Calculate the difference quotient:**
Now we divide by h:

(f(x + h) – f(x)) / h = (2xh + h²) / h

This simplifies to:

2x + h

4. **Final Expression:**
Since h is not equal to zero, we have successfully simplified the difference quotient:

Thus, the difference quotient of f(x) = x² + 5 is 2x + h.

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