To find the equation of the line that passes through the points (6, 7) and (3, 6), we can start by calculating the slope of the line using the slope formula:
Slope (m) = (y2 – y1) / (x2 – x1)
Here, we can assign (x1, y1) = (6, 7) and (x2, y2) = (3, 6). Plugging in these values:
m = (6 – 7) / (3 – 6) = (-1) / (-3) = 1/3
Now that we have the slope, we can use the point-slope form of the equation of a line, which is:
y – y1 = m(x – x1)
We can use one of the points. Let’s use (6, 7):
y – 7 = (1/3)(x – 6)
Next, we will simplify this equation:
y – 7 = (1/3)x – 2
Adding 7 to both sides:
y = (1/3)x + 5
This is the equation of the line in slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept. Thus, the equation that represents the line passing through the points (6, 7) and (3, 6) is:
y = (1/3)x + 5