To find the equation of a line with a given slope and a specific point, we can use the point-slope form of the equation of a line. The point-slope form is expressed as:
y – y1 = m(x – x1)
Where:
- m is the slope of the line.
- (x1, y1) is the given point that the line passes through.
In this problem, we are given:
- Slope (m) = 4
- Point (x1, y1) = (6, 11)
Now we will substitute the slope and the point into the point-slope formula:
y – 11 = 4(x – 6)
Next, we can simplify this equation to find the slope-intercept form of the line (y = mx + b):
- Distribute the slope (4) on the right side:
- Add 11 to both sides to isolate y:
y – 11 = 4x – 24
y = 4x – 24 + 11
y = 4x – 13
So, the equation of the line with a slope of 4 that passes through the point (6, 11) is:
y = 4x – 13