How do you write tan x in terms of sec x?

To express tan x in terms of sec x, we start from the relationships in trigonometry.

We know that:

  • tan x = sin x / cos x
  • sec x = 1 / cos x

From the definition of sec x, we can express cos x in terms of sec x:

cos x = 1 / sec x

Now, substituting this expression into the formula for tan x, we have:

tan x = sin x / (1 / sec x)

This simplifies to:

tan x = sin x * sec x

Next, we need to express sin x in terms of sec x. Using the Pythagorean identity, we know:

sin² x + cos² x = 1

Substituting cos x = 1 / sec x into the identity gives:

sin² x + (1 / sec x)² = 1

Solving for sin² x gives:

sin² x = 1 – (1 / sec² x)

Thus, we have:

sin² x = (sec² x – 1) / sec² x

Taking the square root, we find:

sin x = √((sec² x – 1) / sec² x) = √(sec² x – 1) / sec x

Now substituting this back into our expression for tan x:

tan x = (√(sec² x – 1) / sec x) * sec x

Finally, we simplify to:

tan x = √(sec² x – 1)

In conclusion, we can express tan x in terms of sec x as:

tan x = √(sec² x – 1)

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