To determine which exponential function passes through the points (1, 20) and (2, 80), we can represent an exponential function in the form of y = abx, where a is the initial value and b is the growth factor.
From the first point (1, 20), we substitute into the equation:
20 = ab1 → 20 = ab (1)
Next, using the second point (2, 80):
80 = ab2 → 80 = ab2 (2)
Now we have two equations:
- Equation (1): 20 = ab
- Equation (2): 80 = ab2
We can solve for b by dividing equation (2) by equation (1):
80 / 20 = (ab2) / (ab) → 4 = b
Now that we have b = 4, we can substitute it back into equation (1) to find a:
20 = a(4) → a = 5
Therefore, the exponential function we are looking for is:
y = 5(4)x
To verify, we can check both points:
- At x = 1: y = 5(4)1 = 20
- At x = 2: y = 5(4)2 = 80
Since both points satisfy the function, we have confirmed that the exponential function which goes through the points (1, 20) and (2, 80) is y = 5(4)x.