To find the value of b² – 4ac for the equation x² + 5x + 4 = 0, we first need to identify the coefficients a, b, and c from the standard form of a quadratic equation, which is ax² + bx + c = 0.
In this case, we have:
- a = 1
- b = 5
- c = 4
Now, we can calculate b² – 4ac:
- b² = 5² = 25
- 4ac = 4 * 1 * 4 = 16
Now, substituting these values into the expression:
b² – 4ac = 25 – 16 = 9
Thus, the value of b² – 4ac is 9.