What is the sum of the geometric sequence 2, 10, 50 if there are 8 terms?

The given geometric sequence starts with the terms 2, 10, and 50. To find the sum of this sequence over 8 terms, we first need to identify the common ratio and the formula for the sum of a geometric series.

In a geometric sequence, each term can be found by multiplying the previous term by a constant called the common ratio. Let’s find the common ratio (r) between the first two terms:

r = second term / first term = 10 / 2 = 5

Next, we can verify this ratio with the subsequent terms:

r = third term / second term = 50 / 10 = 5

So, the common ratio is indeed 5.

Now, we can see that the formula for the sum (S) of the first n terms of a geometric sequence is:

Sn = a * (1 – rn) / (1 – r)

Where:

  • Sn is the sum of the first n terms
  • a is the first term
  • r is the common ratio
  • n is the number of terms

Substituting the known values into the formula:

  • a = 2
  • r = 5
  • n = 8

We can now calculate:

S8 = 2 * (1 – 58) / (1 – 5)

Calculating 58 gives us 390625:

S8 = 2 * (1 – 390625) / (1 – 5) = 2 * (-390624) / (-4)

This simplifies to:

S8 = 2 * 97656 = 195312

Therefore, the sum of the first 8 terms of the geometric sequence is 195312.

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