What is the solution of the linear quadratic system of equations y = 25x^2 + 3y = x^2?

To solve the system of equations given by y = 25x^2 and y = x^2, we start by setting the two expressions for y equal to each other:

25x^2 = x^2

Next, we can rearrange this equation:

25x^2 – x^2 = 0

24x^2 = 0

Dividing both sides by 24 gives:

x^2 = 0

Taking the square root of both sides results in:

x = 0

Now that we have the value of x, we can substitute it back into either of the original equations to find the corresponding y value. Using y = 25x^2:

y = 25(0)^2 = 0

Hence, the solution to the linear quadratic system of equations is:

(x, y) = (0, 0)

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