What is the remainder when the polynomial 6x² + 11x + 7 is divided by 2x + 1?

To find the remainder of the polynomial 6x² + 11x + 7 when divided by 2x + 1, we can use the Remainder Theorem. According to this theorem, the remainder of the division of a polynomial f(x) by a linear divisor ax + b can be found by evaluating f(-b/a).

In our case, the divisor is 2x + 1, which means we need to find -b/a. Here, a = 2 and b = 1. Thus, we calculate:

-1/2

Next, we will substitute x = -1/2 into the polynomial 6x² + 11x + 7:

f(-1/2) = 6(-1/2)² + 11(-1/2) + 7

Calculating each term, we get:

  • 6(-1/2)² = 6(1/4) = 3
  • 11(-1/2) = -11/2
  • 7 = 7

Now, summing these values:

f(-1/2) = 3 – 11/2 + 7

To combine these, we convert 7 into halves:

7 = 14/2

So:

f(-1/2) = 3 – 11/2 + 14/2 = 3 + 3/2 = 3 + 1.5 = 4.5

Thus, the remainder when the polynomial 6x² + 11x + 7 is divided by 2x + 1 is 4.5.

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