What is the rate of depreciation if the value of a car is half of its original cost?

To find the rate of depreciation, we can start with the depreciation equation: y = a(1 – r)^t, where:

  • y is the current value of the car,
  • a is the original cost of the car,
  • r is the rate of depreciation, and
  • t is time in years.

In this case, the current value of the car (y) is half of its original cost (a), so we can set up the equation as follows:

0.5a = a(1 – r)^t

Next, we divide both sides by a (assuming a is not zero):

0.5 = (1 – r)^t

At this point, we need to solve for r. Taking the natural logarithm of both sides gives:

ln(0.5) = ln((1 – r)^t)

Using the power rule of logarithms, this simplifies to:

ln(0.5) = t * ln(1 – r)

Now we can express ln(1 – r) in terms of ln(0.5):

ln(1 – r) = rac{ln(0.5)}{t}

To find the rate of depreciation r, we can rewrite this as:

1 – r = e^{ rac{ln(0.5)}{t}}

Thus:

r = 1 – e^{ rac{ln(0.5)}{t}} = 1 – 0.5^{ rac{1}{t}}

Now, depending on the time period t, you can substitute that value into the equation to find the specific rate of depreciation r. For example:

  • If t = 1: r = 1 – 0.5 = 0.5 or 50%
  • If t = 2: r = 1 – rac{1}{
    oot{2}{2}} = 0.2929
    or approximately 29.29%

In conclusion, the rate of depreciation will depend on the time period t. By substituting a specific value for t, you can determine the corresponding rate of depreciation.

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