What is the quotient of 3x² + 17x + 10 divided by x + 5?

To find the quotient of the expression 3x² + 17x + 10 divided by x + 5, we need to use polynomial long division.

Firstly, we arrange the polynomial division:

          _____________
x + 5 | 3x² + 17x + 10

1. Divide the first term of the dividend, 3x², by the first term of the divisor, x, to get 3x.

2. Multiply 3x by the entire divisor (x + 5):
3x * (x + 5) = 3x² + 15x.

3. Subtract this result from the original polynomial:

          3x
          _____________
x + 5 | 3x² + 17x + 10
          - (3x² + 15x)
          _______________
                     2x + 10

4. Now, bring down the next term (if there was one), but in this case, we can proceed directly as we have 2x + 10.

5. Now, divide 2x by x to get 2.

6. Multiply 2 by the entire divisor:

2 * (x + 5) = 2x + 10.

7. Subtract this from 2x + 10:

                 3x + 2
          _____________
x + 5 | 3x² + 17x + 10
          - (3x² + 15x)
          _______________
                     2x + 10
                   - (2x + 10)
                  _______________
                         0

Since the remainder is 0, we find that:

The quotient of 3x² + 17x + 10 divided by x + 5 is: 3x + 2.

This means that you can express the original polynomial as:

3x² + 17x + 10 = (x + 5)(3x + 2).

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