What is the probability of a cross resulting in purple offspring when two heterozygous purple pea plants (Pp x Pp) are bred? What are the genotypes for purple offspring resulting from this cross?

In this genetic cross, we are looking at two heterozygous purple pea plants, represented as Pp x Pp. In pea plants, the allele for purple color (P) is dominant over the allele for white color (p).

To determine the probability of purple offspring, we can set up a Punnett square:

P p
P PP Pp
p Pp pp

From the square, we can see the possible genotypes of the offspring:

  • 1 PP (homozygous dominant)
  • 2 Pp (heterozygous)
  • 1 pp (homozygous recessive)

Now, let’s calculate the probabilities:

  • Probability of offspring being PP: 1 out of 4 (25%)
  • Probability of offspring being Pp: 2 out of 4 (50%)
  • Probability of offspring being pp: 1 out of 4 (25%)

Since both PP and Pp offspring will express the purple phenotype, we add the probabilities of these two genotypes:

  • Probability of purple offspring (PP + Pp): 25% + 50% = 75%

In conclusion, when two heterozygous purple pea plants (Pp x Pp) are bred, there is a 75% probability that the resulting offspring will be purple, with the possible genotypes being PP or Pp.

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