In this genetic cross, we are looking at two heterozygous purple pea plants, represented as Pp x Pp. In pea plants, the allele for purple color (P) is dominant over the allele for white color (p).
To determine the probability of purple offspring, we can set up a Punnett square:
P | p | |
---|---|---|
P | PP | Pp |
p | Pp | pp |
From the square, we can see the possible genotypes of the offspring:
- 1 PP (homozygous dominant)
- 2 Pp (heterozygous)
- 1 pp (homozygous recessive)
Now, let’s calculate the probabilities:
- Probability of offspring being PP: 1 out of 4 (25%)
- Probability of offspring being Pp: 2 out of 4 (50%)
- Probability of offspring being pp: 1 out of 4 (25%)
Since both PP and Pp offspring will express the purple phenotype, we add the probabilities of these two genotypes:
- Probability of purple offspring (PP + Pp): 25% + 50% = 75%
In conclusion, when two heterozygous purple pea plants (Pp x Pp) are bred, there is a 75% probability that the resulting offspring will be purple, with the possible genotypes being PP or Pp.