The name of the ionic compound SnO2 is tin(IV) oxide.
This compound consists of tin (Sn) and oxygen (O) ions. In this case, tin has a +4 oxidation state, which is indicated by the Roman numeral IV in its name. The oxide ion has a -2 charge. To balance the charges in the compound, two oxide ions are needed for each tin ion, resulting in the formula SnO2. Thus, we call this ionic compound tin(IV) oxide.