The correct answer is a) tin(IV) carbonate.
To break this down, the formula Sn(CO3)2 indicates that we have tin (Sn) and carbonate (CO3) in this compound. Tin can have different oxidation states, and in this case, it is in the +4 oxidation state, which is why we refer to it as tin(IV).
The carbonate ion has a -2 charge, and since there are two carbonate ions in the formula, the tin must balance this with a +4 charge, confirming it is in the +4 oxidation state. That’s how we arrive at the name tin(IV) carbonate.