The molecular weight of iron(III) nitrate, Fe(NO3)3, can be calculated by adding the atomic weights of all the atoms in the formula.
Let’s break it down:
- Iron (Fe) has an atomic weight of approximately 55.85 g/mol.
- Nitrogen (N) has an atomic weight of about 14.01 g/mol, and there are 3 nitrogen atoms in the formula.
- Oxygen (O) has an atomic weight of around 16.00 g/mol, and there are 9 oxygen atoms in total (3 groups of NO3).
Now, we can calculate the total molecular weight as follows:
- Molecular weight of Fe = 55.85 g/mol
- Molecular weight of N = 3 × 14.01 g/mol = 42.03 g/mol
- Molecular weight of O = 9 × 16.00 g/mol = 144.00 g/mol
Adding these together gives us:
55.85 g/mol + 42.03 g/mol + 144.00 g/mol = 241.88 g/mol
Therefore, the molecular weight of Fe(NO3)3 is approximately 241.88 g/mol.