What is the molarity of 25 grams of HCl in 250 ml of solution?

To find the molarity of a solution, we use the formula:

Molarity (M) = moles of solute / liters of solution

First, we need to calculate the number of moles of hydrochloric acid (HCl) in the 25 grams. The molar mass of HCl is approximately 36.46 g/mol. Using this, we can calculate the moles:

moles of HCl = mass (g) / molar mass (g/mol)

Substituting in the values:

moles of HCl = 25 g / 36.46 g/mol ≈ 0.687 moles

Next, we need to convert the volume of the solution from milliliters to liters. Since there are 1000 milliliters in a liter:

Volume in liters = 250 ml / 1000 = 0.250 L

Now we can find the molarity:

Molarity (M) = 0.687 moles / 0.250 L ≈ 2.748 M

Therefore, the molarity of 25 grams of HCl in 250 ml of solution is approximately 2.748 M.

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