The molar mass of PbI2 (Lead(II) iodide) is calculated by adding the atomic masses of its constituent elements: lead (Pb) and iodine (I).
Here’s the breakdown:
- Lead (Pb) has an atomic mass of approximately 207.2 g/mol.
- Iodine (I) has an atomic mass of approximately 126.9 g/mol.
Since there are two iodine atoms in PbI2, we multiply the atomic mass of iodine by 2:
126.9 g/mol × 2 = 253.8 g/mol
Now, add the atomic mass of lead to the total mass of iodine:
207.2 g/mol + 253.8 g/mol = 461.0 g/mol
Therefore, the molar mass of PbI2 is 461.0 g/mol.