The molar mass of Ba(OH)₂ (Barium hydroxide) is calculated by adding the atomic masses of its constituent elements. Here’s how it’s done:
- Barium (Ba): 1 atom × 137.33 g/mol = 137.33 g/mol
- Oxygen (O): 2 atoms × 16.00 g/mol = 32.00 g/mol
- Hydrogen (H): 2 atoms × 1.01 g/mol = 2.02 g/mol
Adding these together:
137.33 g/mol (Ba) + 32.00 g/mol (O) + 2.02 g/mol (H) = 171.35 g/mol
Therefore, the molar mass of Ba(OH)₂ is 171.35 g/mol.