What is the Molar Mass of Ba(NO3)2?

The molar mass of Ba(NO₃)₂ (Barium Nitrate) is calculated by adding the atomic masses of all the atoms in the compound. Here’s how it’s done:

• Barium (Ba): 1 atom × 137.33 g/mol = 137.33 g/mol
• Nitrogen (N): 2 atoms × 14.01 g/mol = 28.02 g/mol
• Oxygen (O): 6 atoms × 16.00 g/mol = 96.00 g/mol

Adding these together:

137.33 g/mol + 28.02 g/mol + 96.00 g/mol = 261.35 g/mol

Therefore, the molar mass of Ba(NO₃)₂ is 261.35 g/mol.