What is the molar mass of Ba(NO2)2?

To calculate the molar mass of barium nitrite (Ba(NO₂)₂), we first need to identify the molar masses of each component:

• Barium (Ba) has a molar mass of approximately 137.33 g/mol.
• Nitrogen (N) has a molar mass of about 14.01 g/mol.
• Oxygen (O) has a molar mass of approximately 16.00 g/mol.

Now, let’s break down the formula Ba(NO₂)₂:

• There is 1 atom of barium (Ba).
• There are 2 nitrogen atoms (2 from 2 NO₂). Therefore, we have 2 × 14.01 g/mol = 28.02 g/mol.
• There are 4 oxygen atoms in total (2 from each of the 2 NO₂), which gives us 4 × 16.00 g/mol = 64.00 g/mol.

Now, we can add these values together to find the molar mass of Ba(NO₂)₂:

• Molar mass of Ba = 137.33 g/mol
• Molar mass of 2 N = 28.02 g/mol
• Molar mass of 4 O = 64.00 g/mol

Final calculation:

Molar Mass = 137.33 + 28.02 + 64.00 = 229.35 g/mol

Therefore, the molar mass of Ba(NO₂)₂ is approximately 229.35 g/mol.