To calculate the molar mass of aluminum nitrate, Al(NO3)3, we need to consider the atomic masses of its constituent elements and their quantities in the formula.
1. **Aluminum (Al)**: The atomic mass of aluminum is approximately 26.98 g/mol.
2. **Nitrogen (N)**: The atomic mass of nitrogen is about 14.01 g/mol, and since there are three nitrate groups, we have three nitrogen atoms contributing to the total mass.
3. **Oxygen (O)**: The atomic mass of oxygen is roughly 16.00 g/mol. Each nitrate group has three oxygen atoms, and with three nitrate groups, we have nine oxygen atoms in total.
Now let’s calculate the molar mass:
- Mass of Aluminum = 1 × 26.98 g/mol = 26.98 g/mol
- Mass of Nitrogen = 3 × 14.01 g/mol = 42.03 g/mol
- Mass of Oxygen = 9 × 16.00 g/mol = 144.00 g/mol
Adding these together gives us:
26.98 g/mol + 42.03 g/mol + 144.00 g/mol = 212.01 g/mol
Therefore, the molar mass of Al(NO3)3 is approximately 212.01 g/mol.