What is the maximum amount of C2H2 that can be formed from 50.0 grams of C and 50.0 grams of H?

To determine the maximum amount of acetylene (C₂H₂) that can be formed from 50.0 grams of carbon (C) and 50.0 grams of hydrogen (H), we need to follow these steps:

1. Calculate the moles of carbon and hydrogen:
   • Moles of C = mass of C / molar mass of C = 50.0 g / 12.01 g/mol ≈ 4.16 mol
   • Moles of H = mass of H / molar mass of H = 50.0 g / 1.008 g/mol ≈ 49.60 mol
2. Determine the limiting reactant:

   The balanced chemical equation for the formation of acetylene is:

   2C + H₂ → C₂H₂

   From the equation, 2 moles of C react with 1 mole of H₂ to form 1 mole of C₂H₂.

   Since we have 4.16 moles of C and 49.60 moles of H, the limiting reactant is carbon (C) because it will be consumed first.

3. Calculate the maximum amount of C₂H₂ that can be formed:

   From the balanced equation, 2 moles of C produce 1 mole of C₂H₂.

   Therefore, 4.16 moles of C will produce:

   Moles of C₂H₂ = 4.16 mol C / 2 = 2.08 mol C₂H₂

   Now, convert moles of C₂H₂ to grams:

   Mass of C₂H₂ = moles of C₂H₂ × molar mass of C₂H₂ = 2.08 mol × 26.04 g/mol ≈ 54.16 g

Thus, the maximum amount of acetylene (C₂H₂) that can be formed from 50.0 grams of carbon and 50.0 grams of hydrogen is approximately 54.16 grams.