What is the mass of 1.00 x 10² platinum atoms if the molar mass of platinum is 195.08 g/mol?

To determine the mass of 1.00 x 10² platinum (Pt) atoms, we need to first understand how to convert atoms to grams using the molar mass.

The molar mass of platinum is 195.08 g/mol. This value indicates that one mole of platinum atoms (which contains approximately 6.022 x 10²³ atoms, known as Avogadro’s number) has a mass of 195.08 grams.

First, we find the number of moles in 1.00 x 10² atoms:

Number of moles = Number of atoms / Avogadro’s number

Here, substituting the values:

Number of moles = (1.00 x 10² atoms) / (6.022 x 10²³ atoms/mol)

Calculating this gives:

Number of moles ≈ 1.66 x 10⁻²⁲ moles

Now, to find the mass of these moles of platinum, we use the molar mass:

Mass = Number of moles x Molar mass

Substituting the values:

Mass = (1.66 x 10⁻²² moles) x (195.08 g/mol)

This calculation yields:

Mass ≈ 3.24 x 10⁻²⁰ grams

So, the mass of 1.00 x 10² platinum atoms is approximately 3.24 x 10⁻²⁰ grams.

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