What is the Lewis Structure for Hydrogen Peroxide (H2O2)?

The Lewis structure for hydrogen peroxide (H2O2) can be drawn by following these steps:

1. Count the total number of valence electrons. Hydrogen has 1 valence electron, and oxygen has 6. Since there are 2 hydrogen atoms and 2 oxygen atoms, the total number of valence electrons is (2 × 1) + (2 × 6) = 14.
2. Arrange the atoms. The central atoms are the two oxygen atoms, and the hydrogen atoms are attached to the oxygen atoms. The structure looks like this: H-O-O-H.
3. Place a single bond between each pair of atoms. This uses 2 electrons per bond, so 4 electrons are used in total.
4. Distribute the remaining electrons. After placing the bonds, you have 10 electrons left. Place these as lone pairs on the oxygen atoms. Each oxygen atom will have 2 lone pairs.
5. Check the octet rule. Each oxygen atom should have 8 electrons around it (2 from the bonds and 6 from the lone pairs), and each hydrogen atom should have 2 electrons (from the bond).

The final Lewis structure for H2O2 is:

    H   O   O   H
    |   |   |   |
    H-O-O-H

This structure shows the arrangement of atoms and the distribution of electrons in hydrogen peroxide.