What is the Kb of Acetic Acid at 25 Degrees Celsius if the Ka is 1.8 x 10^-5?

To find the Kb (base dissociation constant) of acetic acid at 25 degrees Celsius, we can use the relationship between Ka, Kb, and Kw, which is the ion product of water. At 25 degrees Celsius, Kw is 1.0 x 10^-14.

The relationship is given by the equation:

Ka × Kb = Kw

Since we have Ka for acetic acid (1.8 x 10^-5), we can rearrange the equation to solve for Kb:

Kb = Kw / Ka

Substituting the values:

Kb = (1.0 x 10^-14) / (1.8 x 10^-5)

Now, calculating the Kb:

Kb ≈ 5.56 x 10^-10

Thus, the Kb of acetic acid at 25 degrees Celsius is approximately 5.56 x 10^-10. This value indicates the strength of the base form of acetic acid (acetate ion) in water.

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