What is the Ka of NH4+ given that the Kb of NH3 is 1.8 x 10^-5?

The relationship between the acid dissociation constant (Ka) of a conjugate acid and the base dissociation constant (Kb) of its corresponding base can be determined using the equation:

Ka × Kb = Kw

where Kw is the ion product of water at 25°C, which equals 1.0 x 10^-14.

Given that the Kb of NH3 (ammonia) is 1.8 x 10^-5, we can rearrange the equation to solve for Ka:

Ka = Kw / Kb

Substituting the known values:

Ka = (1.0 x 10^-14) / (1.8 x 10^-5)

Calculating this gives:

Ka ≈ 5.56 x 10^-10

Therefore, the Ka of NH4+ (the conjugate acid of NH3) is approximately 5.56 x 10^-10. This low value indicates that NH4+ is a weak acid, which is consistent with the behavior of its conjugate base, NH3.

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