What is the fully factored form of 32a^3 + 12a^2 + 4a^2 + 8a + 3 + 4a + 8a^2 + 3a + 12a^2 + 3a + 1 + 12a + 3a^2 + a?

To find the fully factored form of the polynomial 32a^3 + 12a^2 + 4a^2 + 8a + 3 + 4a + 8a^2 + 3a + 12a^2 + 3a + 1 + 12a + 3a^2 + a, we first need to combine like terms and reorganize the expression.

Combining the like terms, we get:

  • 32a^3
  • (12a^2 + 4a^2 + 8a^2 + 12a^2 + 3a^2) = 39a^2
  • (8a + 4a + 3a + 12a + a) = 28a
  • + 3 (constant term)

Now the polynomial is:

32a^3 + 39a^2 + 28a + 3

Next, we can look for common factors or use polynomial long division or synthetic division to find roots. By testing small integer values (like 1 or -1) or using the Rational Root Theorem, we can find factors. After some trials, we may find that this polynomial can be decomposed into:

(8a + 3)(4a^2 + 5a + 1)

We can further check if the quadratic factor can be factored. The expression 4a^2 + 5a + 1 can be checked for roots and we find that it cannot be factored further with integers. Thus, our original polynomial can be expressed in its fully factored form as:

(8a + 3)(4a^2 + 5a + 1)

This gives us the simplest form presentable for an algebraic expression.

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