The neutralization of aluminum hydroxide (Al(OH)3) by sulfuric acid (H2SO4) can be represented by the following balanced chemical equation:
2 Al(OH)3 + 3 H2SO4 → Al2(SO4)3 + 6 H2O
In this reaction, two moles of aluminum hydroxide react with three moles of sulfuric acid to produce one mole of aluminum sulfate (Al2(SO4)3) and six moles of water (H2O). This balanced equation shows how an acid reacts with a base, resulting in the formation of a salt and water, which is what we refer to as neutralization.